(6^5+7x)=(2^3-2x)

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Solution for (6^5+7x)=(2^3-2x) equation:



(6^5+7x)=(2^3-2x)
We move all terms to the left:
(6^5+7x)-((2^3-2x))=0
We get rid of parentheses
7x-((2^3-2x))+6^5=0
We calculate terms in parentheses: -((2^3-2x)), so:
(2^3-2x)
We get rid of parentheses
-2x+2^3
We add all the numbers together, and all the variables
-2x+8
Back to the equation:
-(-2x+8)
We add all the numbers together, and all the variables
7x-(-2x+8)+7776=0
We get rid of parentheses
7x+2x-8+7776=0
We add all the numbers together, and all the variables
9x+7768=0
We move all terms containing x to the left, all other terms to the right
9x=-7768
x=-7768/9
x=-863+1/9

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